(b^3+4b^2-6b+2)=(b-1)

Solution for (b^3+4b^2-6b+2)=(b-1) equation:

Simplifying
(b3 + 4b2 + -6b + 2) = (b + -1)

Reorder the terms:
(2 + -6b + 4b2 + b3) = (b + -1)

Remove parenthesis around (2 + -6b + 4b2 + b3)
2 + -6b + 4b2 + b3 = (b + -1)

Reorder the terms:
2 + -6b + 4b2 + b3 = (-1 + b)

Remove parenthesis around (-1 + b)
2 + -6b + 4b2 + b3 = -1 + b

Solving
2 + -6b + 4b2 + b3 = -1 + b

Solving for variable 'b'.

Reorder the terms:
2 + 1 + -6b + -1b + 4b2 + b3 = -1 + b + 1 + -1b

Combine like terms: 2 + 1 = 3
3 + -6b + -1b + 4b2 + b3 = -1 + b + 1 + -1b

Combine like terms: -6b + -1b = -7b
3 + -7b + 4b2 + b3 = -1 + b + 1 + -1b

Reorder the terms:
3 + -7b + 4b2 + b3 = -1 + 1 + b + -1b

Combine like terms: -1 + 1 = 0
3 + -7b + 4b2 + b3 = 0 + b + -1b
3 + -7b + 4b2 + b3 = b + -1b

Combine like terms: b + -1b = 0
3 + -7b + 4b2 + b3 = 0

The solution to this equation could not be determined.